A man has to cover a distance of 387 km in 18 hours. If he covers two – third of this distance in $$\frac{6}{9}$$ of the time, then what should his speed (in km/hr) be to cover the remaining distance in the time left?

Correct option is A

Given:

Total distance to be covered = 387 km

Total time available = 18 hours

Formula Used:

Speed = $$\frac{\text{Distance}}{\text{Time}}$$​​

Solution: 

Two-thirds of the distance = $$\frac23$$​ × 387 = 258 km

Time taken for this part = $$\frac69$$​ × 18 = 12 hours

Remaining distance = 387 – 258 = 129 km

Time left = 18 – 12 = 6 hours

Speed required for remaining distance = $$\frac{129}{6}$$​ = 21.5 km/hr