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A machine member is subjected to fluctuating stress, σ=σ0σ = σ_0σ=σ0​ cos(5π t). The endurance limit of the material is 350 MPa and the yield str
Question

A machine member is subjected to fluctuating stress, σ=σ0σ = σ_0 cos(5π t). The endurance limit of the material is 350 MPa and the yield strength is 500 MPa. If the factor of safety used in the design is 3.5, then the maximum allowable stress σ0σ_0​ in MPa according to soderberg fatigue criteria is

A.

10

B.

200

C.

100

D.

50

Correct option is C

Given:Fluctuating stress: σ=σ0cos(5πt)Stress amplitude: σa=σ0Mean stress: σm=0(purely alternating stress)Endurance limit (σe):350 MPaYield strength (σy):500 MPaFactor of safety (FOS): 3.5Soderberg Fatigue EquationThe Soderberg criterion for combined alternating and mean stresses is:σaσe+σmσy=1FOSFor purely alternating stress (σm=0):σ0σe=1FOSSolve for σ0Substitute the given values:σ0350=13.5=>σ0=3503.5=100 MPa\begin{aligned}&\textbf{Given:} \\&\text{Fluctuating stress: } \sigma = \sigma_0 \cos(5\pi t) \\&\quad \bullet \text{Stress amplitude: } \sigma_a = \sigma_0 \\&\quad \bullet \text{Mean stress: } \sigma_m = 0 \quad (\text{purely alternating stress}) \\&\text{Endurance limit } (\sigma_e): 350 \, \text{MPa} \\&\text{Yield strength } (\sigma_y): 500 \, \text{MPa} \\&\text{Factor of safety (FOS): } 3.5 \\[1em]&\textbf{Soderberg Fatigue Equation} \\&\text{The Soderberg criterion for combined alternating and mean stresses is:} \\&\frac{\sigma_a}{\sigma_e} + \frac{\sigma_m}{\sigma_y} = \frac{1}{\text{FOS}} \\&\text{For purely alternating stress } (\sigma_m = 0): \\&\frac{\sigma_0}{\sigma_e} = \frac{1}{\text{FOS}} \\[1em]&\textbf{Solve for } \sigma_0 \\&\text{Substitute the given values:} \\&\frac{\sigma_0}{350} = \frac{1}{3.5} \\&\Rightarrow \sigma_0 = \frac{350}{3.5} = \boxed{100 \, \text{MPa}}\end{aligned}​​

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