If the load acting on the ball bearing is increased 2 times its life will

Correct option is C

​$$\textbf{Bearing Life Equation:} \\L \propto \left( \frac{1}{P} \right)^3 \\\\\text{Where:} \\L = \text{bearing life (in revolutions or hours)} \\P = \text{load acting on the bearing} \\\text{For ball bearings, exponent } = 3 \\\\\textbf{Given:} \\\text{Load is increased 2 times, i.e.,} \\P_2 = 2P_1 \\\\\text{Using the equation:} \\\frac{L_2}{L_1} = \left( \frac{P_1}{P_2} \right)^3 = \left( \frac{1}{2} \right)^3 = \frac{1}{8} \\\\\text{The life will become one-eighth, i.e.,} \\\boxed{\text{Life will reduce to } \frac{1}{8} \text{th of original life}}$$​​