arrow
arrow
arrow
A circular path is 800 m long. Beena and Arun run in opposite directions from the same point A on the path at the same time. They continue to run afte
Question

A circular path is 800 m long. Beena and Arun run in opposite directions from the same point A on the path at the same time. They continue to run after they meet for the first time. Beena runs another 531353\frac{1}{3} seconds to arrive at A, while Arun runs another 2 minutes to get to point A.

Which of the following statements is/are correct?

Statement I: The speed of Beena is 6 m/sec.

Statement II: The ratio of the speeds of Arun and Beena is 2 : 3.

A.

Neither I nor II

B.

II only

C.

I and II

D.

I only

Correct option is C

Given:

  • Circular track = 800 m
  • Beena and Arun run in opposite directions starting from point A at the same time.
  • After meeting,
    • Beena takes 53⅓ sec = 160/3 sec to return to point A.
    • Arun takes 2 min = 120 sec to return to point A.

We need to evaluate:

  • Statement I: Beena’s speed = 6 m/s
  • Statement II: Ratio of Arun’s speed to Beena’s = 2 : 3

Solution:

If two people start from the same point and run in opposite directions, they meet once their combined distance = full circle (800 m).

Let Beena's speed = B
Let Arun's speed = A

They meet after time t=800A+BAfter meeting: Beena takes 1603 sec to cover the remaining distance back to A. Arun takes 120 sec to return to A.So: Distance Beena runs after meeting =B1603 Distance Arun runs after meeting =A120These distances sum up to the total circle:B1603+A120=800(Equation 1)\text{They meet after time } t = \frac{800}{A + B} \\[1.5ex]\textbf{After meeting:} \\[1ex]\bullet\ \text{Beena takes } \frac{160}{3} \text{ sec to cover the remaining distance back to A.} \\[0.5ex]\bullet\ \text{Arun takes 120 sec to return to A.} \\[1.5ex]\textbf{So:} \\[1ex]\bullet\ \text{Distance Beena runs after meeting } = B \cdot \frac{160}{3} \\[0.5ex]\bullet\ \text{Distance Arun runs after meeting } = A \cdot 120 \\[1.5ex]\text{These distances sum up to the total circle:} \\[1.5ex]B \cdot \frac{160}{3} + A \cdot 120 = 800 \quad \text{(Equation 1)}​​

Let’s try Beena’s speed = 6 m/s (to check Statement I)

Then:

 Distance Beena runs after meeting=61603=320 meters So Arun’s remaining distance=800320=480 meters Arun’s speed=480120=4 m/s\bullet\ \text{Distance Beena runs after meeting} = 6 \cdot \frac{160}{3} = 320 \text{ meters} \\[1ex]\bullet\ \text{So Arun's remaining distance} = 800 - 320 = 480 \text{ meters} \\[1ex]\bullet\ \text{Arun's speed} = \frac{480}{120} = 4 \text{ m/s}​​

So, speeds are:

  • Beena = 6 m/s
  • Arun = 4 m/s

Then the ratio:

  • Arun : Beena = 4 : 6 = 2 : 3

This matches Statement II

Final Checks:

Statement I:

Beena’s speed = 6 m/s → True

Statement II:

Arun : Beena = 2 : 3 → True

Final Answer: (C) Both I and II are correct.


Free Tests

Free
Must Attempt

SSC GD PYP (Held on 4 Feb 2025 S1)

languageIcon English
  • pdpQsnIcon80 Questions
  • pdpsheetsIcon160 Marks
  • timerIcon60 Mins
languageIcon English
Free
Must Attempt

Hindi Section Test 1

languageIcon English
  • pdpQsnIcon20 Questions
  • pdpsheetsIcon40 Marks
  • timerIcon12 Mins
languageIcon English
Free
Must Attempt

SSC GD Constable Full Mock Test 1

languageIcon English
  • pdpQsnIcon80 Questions
  • pdpsheetsIcon160 Marks
  • timerIcon60 Mins
languageIcon English

Similar Questions

test-prime-package

Access ‘IB ACIO’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
368k+ students have already unlocked exclusive benefits with Test Prime!
Our Plans
Monthsup-arrow