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    A circular path is 800 m long. Beena and Arun run in opposite directions from the same point A on the path at the same time. They continue to run afte
    Question

    A circular path is 800 m long. Beena and Arun run in opposite directions from the same point A on the path at the same time. They continue to run after they meet for the first time. Beena runs another 531353\frac{1}{3} seconds to arrive at A, while Arun runs another 2 minutes to get to point A.

    Which of the following statements is/are correct?

    Statement I: The speed of Beena is 6 m/sec.

    Statement II: The ratio of the speeds of Arun and Beena is 2 : 3.

    A.

    Neither I nor II

    B.

    II only

    C.

    I and II

    D.

    I only

    Correct option is C

    Given:

    • Circular track = 800 m
    • Beena and Arun run in opposite directions starting from point A at the same time.
    • After meeting,
      • Beena takes 53⅓ sec = 160/3 sec to return to point A.
      • Arun takes 2 min = 120 sec to return to point A.

    We need to evaluate:

    • Statement I: Beena’s speed = 6 m/s
    • Statement II: Ratio of Arun’s speed to Beena’s = 2 : 3

    Solution:

    If two people start from the same point and run in opposite directions, they meet once their combined distance = full circle (800 m).

    Let Beena's speed = B
    Let Arun's speed = A

    They meet after time t=800A+BAfter meeting: Beena takes 1603 sec to cover the remaining distance back to A. Arun takes 120 sec to return to A.So: Distance Beena runs after meeting =B1603 Distance Arun runs after meeting =A120These distances sum up to the total circle:B1603+A120=800(Equation 1)\text{They meet after time } t = \frac{800}{A + B} \\[1.5ex]\textbf{After meeting:} \\[1ex]\bullet\ \text{Beena takes } \frac{160}{3} \text{ sec to cover the remaining distance back to A.} \\[0.5ex]\bullet\ \text{Arun takes 120 sec to return to A.} \\[1.5ex]\textbf{So:} \\[1ex]\bullet\ \text{Distance Beena runs after meeting } = B \cdot \frac{160}{3} \\[0.5ex]\bullet\ \text{Distance Arun runs after meeting } = A \cdot 120 \\[1.5ex]\text{These distances sum up to the total circle:} \\[1.5ex]B \cdot \frac{160}{3} + A \cdot 120 = 800 \quad \text{(Equation 1)}​​

    Let’s try Beena’s speed = 6 m/s (to check Statement I)

    Then:

     Distance Beena runs after meeting=61603=320 meters So Arun’s remaining distance=800320=480 meters Arun’s speed=480120=4 m/s\bullet\ \text{Distance Beena runs after meeting} = 6 \cdot \frac{160}{3} = 320 \text{ meters} \\[1ex]\bullet\ \text{So Arun's remaining distance} = 800 - 320 = 480 \text{ meters} \\[1ex]\bullet\ \text{Arun's speed} = \frac{480}{120} = 4 \text{ m/s}​​

    So, speeds are:

    • Beena = 6 m/s
    • Arun = 4 m/s

    Then the ratio:

    • Arun : Beena = 4 : 6 = 2 : 3

    This matches Statement II

    Final Checks:

    Statement I:

    Beena’s speed = 6 m/s → True

    Statement II:

    Arun : Beena = 2 : 3 → True

    Final Answer: (C) Both I and II are correct.


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