A can finish a work in 16 days, and B can do the same work in 12 days. With the help of C, they completed the work in 4 days. In how many days can C alone do the same work?
Given:
A can do the work in 16 days
B can do the work in 12 days
A + B + C together finish the work in 4 days
Formula Used:
Work per day =
Solution:
Assume the total work = LCM of 16, 12, and 4 = 48 units
A’s 1-day work = = 3 units/day
B’s 1-day work = = 4 units/day
A + B + C together do = = 12 units/day
Now compute C’s 1-day work:
C's work/day = 12 - (A + B) = 12 - (3 + 4) = 5 units/day
Now, C alone would take:
= days
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