A, B and C can complete a piece of work in 8, 10 and 12 days, respectively. In how many days would all of them complete the same work, working together?

Correct option is B

Given:

A can do work in 8 days

B can do the same work in 10 days

C can do the work in 12 days

Formula Used:

Let total work be 1.

Then work done 1 day =$$\frac{1}{Total\ time\ to\ work}$$​​

Solution:

A’s one day’s work = $$\frac{1}{8}$$​​

B’s one day’s work =$$\frac{1}{10}$$​​

C’s one day’s work =$$\frac{1}{12}$$​​

A,B and C’s one day work together =$$\frac{1}{8}+\frac{1}{10}+\frac{1}{12}$$​​

​$$= \frac{15+12+10}{120}=\frac{37}{120}$$​​

Time taken by all three working together =$$\frac{1}{\frac{37}{120}} = \frac{120}{37}days$$​​