A 300-meter-long train can cross a 190-meter-long platform in 14 seconds. If the speed of the train increased by 20%, then find the time (in seconds) taken by the train to cross a man with a speed of 10.8 km/hr in the opposite direction.

Correct option is C

Speed of train = $$\frac{300 + 190}{14}$$​
= 35 m/sec
Speed of the man = 10.8×$$\frac{5}{18}$$​=3 m/sec

New speed of train = 35×$$\frac{120}{100}$$​=42 m/sec
Required time = $$\frac{300}{42 + 3}$$ = 6.67 seconds