10 men can complete a task in 18 days. After 6 days, 5 more men join. In how many days the remaining work will be completed? 

Correct option is D

Given:
10 men can do a work in 18 days

Solution:

Let one men work in one day = 1

Total work = 10 × 18 = 180

Now,

6 days work of 10 men = 10 × 6 = 60

Remaining work = 180 - 60 = 120

After 6 days 5 men join

Total men = 5 + 10 = 15

Days in remaining work completed = $$\frac{120}{15}$$​ = 8 days

The required number of days is 8 days.

Thus, correct answer is (d ) 8