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UPSSSC-JE’21 CE: Daily Practice Quiz. 15-November-2021

Know your strengths and practice your concepts with this quiz on UPSSSC-JE Recruitment 2021. This quiz for UPSSSC-JE Recruitment 2021 is designed specially according to UPSSSC-JE Syllabus 2021.

Quiz: Civil Engineering

Each question carries 1 mark
Negative marking: 1/4 mark
Time: 8 Minutes

Q1. The pressure in meters of oil (specific gravity 0.85) equivalent to 42.5m of water is______:
(a) 12.5 m
(b) 50 m
(c) 52.5m
(d) 85m

Q2. You are asked to construct a massive concrete dam. The type of cement you will use is:
(a) ordinary Portland cement
(b) Rapid hardening Portland cement
(c) Low heat cement
(d)Blast furnace slag cement

Q3. The addition of CaCl_2 in concrete results in
(i) increased shrinking
(ii) decreased setting time
(iii) decreased shrinkage
(iv) increased setting time
(a) only (i) and (iv)
(b) only (iv)
(c) only (i)
(d) only (i) and (ii)

Q4. Addition of sugar in concrete result in………
(a) Increase in setting time by about 1 hr.
(b) Increase in setting time by about 4 hr.
(c) Decrease in setting time by about 1 hr.
(d) Decrease in setting time by about 4 hr.

Q5. Find the coefficient of hardness, if the loss in weight is 25 gm as per dory abrasion test:
(a) 11.4
(b) 11.5
(c) 11.6
(d) 11.1

Q6. A tube well having a capacity of 4 m³/hour operates for 20 hours each day during the irrigation season. How much area can be commanded if the irrigation interval is 20 days and depth of irrigation is 7 cm?
(a) 1.71 × 10^4 m²
(b) 1.14 × 10^4 m²
(c) 22.9 × 10^4 m²
(d) 2.29 × 10^4 m²


S1. Ans. (b)
Sol. Pressure of oil = Pressure of water
(ρgh ) oil = (ρgh) water
(0.85 × 1000 × 9.81× h) = (1000 × 9.81 × 42.5)

h = 50 m

S2. Ans.(c)
Sol. Low heat cement is preferred to construct a massive concrete dam because it has less heat of hydration.

S3. Ans.(d)
Sol. Calcium chloride is used as accelerators. it decrease the setting time of concrete and Increase shrinkage of concrete.

S4. Ans.(b)
Sol. Sugar is used as retarder in concrete. It increase in setting time by about 4 hr.

S5. Ans.(c)
Sol. given, loss in weight = 25 gm
▭(coefficient of hardness= 20-(loss in weight in gm.)/3)

S6. Ans.(d)
Sol. Q = 4 × 20 = 80 m³/day
Q = 9.26 × 10^(-4) m³/sec
B = 20 days
∆ = 7 cm. = 0.07 m.
Duty of outlet
D = (8.64 B)/∆
D = (8.64×20)/0.07
D = 2468 Ha/cumec
Area (A) = D ×Q
= 2468 × 9.26 × 10^(-4)
= 2.296 Ha
= 2.29 × 10^4 m²

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