UPPSC-LECTURER’21 EE: Daily Practices Quiz 16-Dec-2021

UPPSC polytechnic lecturer  2021

UPPSC Technical Lecturer Eligibility Criteria 2021. Uttar Pradesh Public Service Commission has released the official notification for the recruitment of Principal, Lecturer, Librarian, and Workshop Superintendent. The Online application has been started on 15th September 2021 and the last date to apply online is 15th October 2021. The recruitment is for a total of 1370 UPPSC Polytechnic Lecturer Vacancies.

Exam Date: 22/12/2021

UPPSC polytechnic lecturer QUIZ: EE

UPPSC-LECTURER’21 EE: Daily Practices Quiz 16-Dec-2021

Each question carries 3 marks.
Negative marking: 1 mark each or 1/3rd
Total Questions: 06
Time: 08 min.

Q1. Siemens can be used as a unit for……
(a) Measurement of resistance
(b) Measurement of flux density
(c) Measurement of conductance
(d) Measurement of electric field

Q2. The maximum power that can be transmitted through a transmission line of resistance R ohm and reactance X ohm, if it satisfies the condition:
(a) X=R
(b) X=3R
(c) X=√2 R
(d) X=√3 R

Q3. The equivalent star impedance per phase of a balanced delta connected load of value (9+j6) ohm, per phase is given by:
(a) (3+j2) Ω
(b) (27+j18) Ω
(c) (6+j9) Ω
(d) (9-j6) Ω

Q4. For a feedback control system of type-2, the steady state error for a ramp input is….
(a) Constant
(b) Zero
(c) Infinity
(d) Indeterminate

Q5. If Am is the amplitude of the message signal and Ac is the amplitude of the carrier
Signal, then modulation index is:
(a) Am/Ac
(b) Ac/Am
(c) Ac Am
(d) Ac+Am

Q6. If the Amplitude of the message signal is 4V and amplitude of the carrier signal is
6V then percentage of modulation is
(a) 33.33%
(b) 66.66%
(c) 50%
(d) 60%

SOLUTIONS

S1. Ans.(c)
Sol.

S2. Ans.(d)
Sol. From MPPT, X=√3 R

S3. Ans.(a)
Sol. Zγ=Z∆/3=((9+j6) )/3=(3+j2)Ω

S4. Ans.(b)
Sol. For ramp input type-2 system, K_v=ꝏ
∴ess=1/kv =1/ꝏ=0

S5. Ans.(a)
Sol. Modulation index
m =(Amplitude of message signal)/(amplitude of carrier signal)
=Am/Ac

S6. Ans.(b)
Sol. Modulation index
=Am/(Ac )
=4/6 =2/3
∴ % modulation = 2/3×100%= 66.66%

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