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# PSPCL-JE’21 EE: Daily Practices Quiz 27-Oct-2021

## PSPCL RECRUITMENT 2021

Punjab State Power Corporation Ltd. (PSPCL), a power generating and distributing company of the Government of Punjab state, has released the notification for recruitment to the post of Clerk, Revenue Accountant, Junior Engineer (Electrical), Assistant Lineman & Assistant Sub Station Attendant Posts.
A total of 75 vacancies have been announced for the recruitment process of JE ELECTRICAL Engineering.

Exam Dates: 10 N0V-21 to 17 Nov-21

## PSPCL-JE’21 EE: Daily Quiz

PSPCL-JE’21 EE: Daily Practices Quiz 27-Oct-2021

Each question carries 1 mark.
Negative marking: 1/4 mark
Total Questions: 06
Time: 06 min.

Q1. Find the number of strands of ACSR conductor for 3-layer transmission line?
(a) 1
(b) 3
(c) 19
(d) 37

Q2. At standstill, in a three-phase induction motor, the ratio of slip speed to speed at which stator magnetic field rotates is equal to……….
(a) 3
(b) 0
(c) 2
(d) 1

Q3. Which gate is used when an output is desired to be complement of the input?
(a) NOT Gate
(b) AND Gate
(c) XOR gate
(d) OR Gate

Q4. In a 4-pole, 25 KW, 200 V wave wound dc shunt generator, the current in each parallel path will be:
(a) 125 A
(b) 31.25 A
(c) 250 A
(d) 62.5 A

Q5. Which of the following is not a Maxwell’s equation?
(a) ∆×E= -∂B/∂t
(b) ∆.E= -B
(c) ∆.D=ρ
(d) ∆.B= 0

Q6. In a dynamometer type wattmeter, the pressure coil connected across the load terminal is
(a) Highly inductive
(b) Highly capacitive
(c) Highly resistive
(d) Non inductive

## SOLUTIONS

S1. Ans.(c)
Sol. Number of strands for ‘n’ layers=3n^2-3n+1=3×3^2-(3×3)+1=19.

S2. Ans.(d)
Sol. The slip speed of an induction motor is defined as the difference between synchronous speed and rotor speed.
i.e., N_slip=N_S-N_r
stator magnetic field rotates at synchronous speed.
At standstill condition, N_r=0
∴required ratio=N_s/N_s =1.

S3. Ans.(a)
Sol. A NOT gate is a logic gate that inverts the digital input signal. For this reason, a NOT gate is sometimes is referred to as an inverter.

S4. Ans.(d)
Sol. I_total=P/V=(25×1000)/200=125 A
For WAVE wound: number of parallel paths=2
∴ the current in each parallel path=I_total/2=125/2=62.5 A

S5. Ans.(b)
Sol. Max well’s equations
(i) ∇. D ⃗=ρ or ∇. E = ρ/ϵ_o → Gauss law
(ii) ∇.B ⃗ = O → Gauss’ law of magnetism
(iii) ∇ × E = – ∂B/∂t = – B’ → Faraday’s law
(iv) ∇ × H = ∂D/∂t + J → Amperes circuital law

S6. Ans.(c)
Sol. In a dynamometer type wattmeter, the pressure coil connected across the load terminal is highly Resistive.

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