Know your strengths and practice your concepts with this quiz on NHPC JE Recruitment 2021. This quiz for NHPC JE Recruitment 2021 is designed specially according to NHPC Syllabus 2021.
Quiz: Civil Engineering
Each question carries 1 mark
Negative marking: 1/4 mark
Time: 8 Minutes
Q1. Bitumen emulsion is:
(a) Liquid containing bitumen in suspension.
(c) Used as anti-corrosive paint.
(d) All the above.
Q2. Tortuosity of a meandering river is always
(a) equal to 1
(b) greater than 1
(c) less than 1
(d) greater than 0.1
Q3. A structural member subject to compressive force in a direction parallel to its longitudinal axis is called
(d) Any one of above
Q4. For drawing ILD, what value of test load is assumed?
(a) 1 unit
(c) Depends upon structure
Q5. Calculate the annual depreciation (Rs.) of a machine having initial cost of Rs. 10,000. The scrap value is Rs. 1,000 and useful life of 30 years.
Q6. For maximum sagging bending moment at support in a continuous RC beam, live load should be placed on
(a) spans adjacent to the support plus alternate spans
(b) al the spans except the spans adjacent to the support
(c) spans next to the adjacent spans of the support plus alternate spans
(d) spans adjacent to supports only
Sol. Bitumen emulsion a liquid containing bitumen in suspension. It is used for surface dressing; patch repair works and maintenance in rainy season.
Sol. Tortuosity = (Curved length along the channel)/(Direct axial length)
This ratio is always greater than 1.
Sol. Stanchion is a structural member subjected to compression force in a direction parallel to its longitudinal axis.
Sol. 1unit load is assumed for drawing the influence load diagram. 1unit load is assumed because calculations are easy and then actual load are multiplied with the results obtained to calculate further.
Original cost = 10,000
Scrap value = 1000
Design life = 30 years
Annual deprecation is given by (D)
D=(original cost-scrap value)/(Life in years)
Sol. the maximum moment or shear force at a section depends on the position of the live load.
– For maximum positive span moment at midpoint, load span and all other alternate span.
– For maximum positive support moment, unload the span on either side of the support and load the next spans.
– For maximum negative span moment at midpoint, load the adjacent spans on either side of the span and all other alternate spans.
– For maximum negative moment at support, load the two spans adjacent to the support and all other alternate spans.