NHPC-JE'21 CE: Daily Practices Quiz. 20-Oct-2021 |_00.1
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NHPC-JE’21 CE: Daily Practices Quiz. 20-Oct-2021

Know your strengths and practice your concepts with this quiz on NHPC JE Recruitment 2021. This quiz for NHPC JE Recruitment 2021 is designed specially according to NHPC Syllabus 2021.

Quiz: Civil Engineering
Exam: NHPC-JE
Topic: Miscellaneous

Each question carries 1 mark
Negative marking: 1/4 mark
Time: 8 Minutes

Q1. A rod of dimension 20 mm × 20 mm is carrying an axial tensile load of 10 kN. If the modulus of elasticity is 250 MPa. Then the strain induced due to this load would be __________.
(a) 0.1
(b) 0.25
(c) 0.2
(d) 10

Q2 Which of the following represents the approximate overflow rate (liters/hours/m²) for the plain sedimentation tank?
(a) 500 – 750
(b) 800 – 1200
(c) 1200 – 1520
(d) 1650 – 2500

Q3. The spacing of main bars in a RCC slab shall not be more than:
(a) Three times the effective depth of the slab or 300 mm whichever is less
(b) Four times the effective depth of the slab or 450 mm whichever is less
(c) Three times the total depth of the slab or 300 mm whichever is less
(d) 300 mm

Q4. The maximum gradient for hill road is
(a) 1 IN 15
(b) 1 IN 20
(c) 1 IN 5
(d) 1 IN 25

Q5. Find the plinth area of building if a building built up area 350m² is constructed with a courtyard of 5.5 × 6.5m inside the building
(a) 314.24 m²
(b) 314.25 m²
(c) 314.26 m²
(d) 314.27 m²

Q6. In a closed traverse pentagon, the sum of interior angles is equal to ___________.
(a) 6 × 90°
(b) 4 × 90°
(c) 6 × 180°
(d) 5 × 90

Solutions

S1. Ans.(a)
Sol. Given that
P = 10 kN
A = 20 × 20 mm²
E = 250 MPa
We know that
δL=PL/AE
δL/L=P/AE
Strain=(10×10^3)/(20×20×10^(-6)×250×10^6 )
Strain =0.1

S2. Ans.(a)
Sol. Surface overflow rate for plain sedimentation tank is 12,000 to 18,000 l/day/m² or 500 to 750 l/hours/m² while surface overflow rate for sedimentation with coagulation is 24,000 to 30,000 l/day/m² or 1000 to 1250 l/hours/m².

S3. Ans.(a)
Sol. Maximum Spacing in bar –
(i) For Main bar-
Maximum spacing ≯ 3d (or) 300 mm

(ii) For Distribution bar-
Maximum spacing ≯ 4d (or) 450 mm
Where – d→ effective depth

S4. Ans.(a)
Sol. As per IRC, the maximum gradient is taken as follows-
(i) for plain roads = 1 in 20 or 5%.
(ii) for Hill roads = 1 in 15 or 6.67%.

S5. Ans.(b)
Sol. Built up area = 350 m²
Courtyard area = 5.5 × 6.5 m² = 35.75 m²
Plinth area = 350 – 35.75 = 314.25 m²

S6. Ans.(a)
Sol. If n is the no. of sides of a closed traverse, then total sum of interior will be = (2n – 4) × 90°
n = no. of sides
In Question, Pentagon is given, hence (n) = 5
Sum of interior angle = (2 × 5 – 4) × 90° = 6 × 90°

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