Q1.
A wire of a given material has length l and cross-sectional area A , and its resistance is 9 Ω. Another wire of the same material has length l/3 and cross-sectional area 3A. What will be the resistance of the second wire?
Answer & Solution
Correct option is D
The correct answer is (D) 1 Ω
Explanation:
• The resistance (R) of a wire is directly proportional to its length (L) and inversely proportional to its cross-sectional area (A).
• The formula is: R = ρ(L/A), where ρ (rho) is the resistivity of the material.
• For the first wire: R₁ = ρ(L/A) = 9 Ω.
• For the second wire, the material is the same, so ρ is constant. The new length is L/3, and the new area is 3A.
• R₂ = ρ * ((L/3) / (3A)) = ρ * (L / 9A) = (1/9) * ρ(L/A).
• Since ρ(L/A) is 9 Ω, R₂ = (1/9) * 9 Ω = 1 Ω.
Information Booster:
• Resistivity (ρ): Resistivity is an intrinsic property of the material and does not change when the physical dimensions (length or area) change, as long as temperature remains constant.
• Thick vs. Thin wires: Thicker wires (larger Area) have lower resistance, much like a wider pipe allows more water to flow easily. Shorter wires also have lower resistance.
• Wire Stretching: If a wire is *stretched* to 3 times its length, its area automatically becomes 1/3rd to conserve volume. In that case, the resistance would become 9 times the original.
Additional Knowledge:
• Options A, B, and C: These are common mathematical errors arising from incorrectly applying the fractions in the denominator or failing to account for both the change in length and area simultaneously.
Explanation:
• The resistance (R) of a wire is directly proportional to its length (L) and inversely proportional to its cross-sectional area (A).
• The formula is: R = ρ(L/A), where ρ (rho) is the resistivity of the material.
• For the first wire: R₁ = ρ(L/A) = 9 Ω.
• For the second wire, the material is the same, so ρ is constant. The new length is L/3, and the new area is 3A.
• R₂ = ρ * ((L/3) / (3A)) = ρ * (L / 9A) = (1/9) * ρ(L/A).
• Since ρ(L/A) is 9 Ω, R₂ = (1/9) * 9 Ω = 1 Ω.
Information Booster:
• Resistivity (ρ): Resistivity is an intrinsic property of the material and does not change when the physical dimensions (length or area) change, as long as temperature remains constant.
• Thick vs. Thin wires: Thicker wires (larger Area) have lower resistance, much like a wider pipe allows more water to flow easily. Shorter wires also have lower resistance.
• Wire Stretching: If a wire is *stretched* to 3 times its length, its area automatically becomes 1/3rd to conserve volume. In that case, the resistance would become 9 times the original.
Additional Knowledge:
• Options A, B, and C: These are common mathematical errors arising from incorrectly applying the fractions in the denominator or failing to account for both the change in length and area simultaneously.