Q1.
A cyclist increases her speed from 6 m/s to 12 m/s in 3 seconds on a straight road. What is her acceleration during this period?
Answer & Solution
Correct option is A
The correct answer is (A) 2 m/s²
Explanation:
• Acceleration is defined as the rate of change of velocity with respect to time.
• The mathematical formula for uniform acceleration is: a = (v - u) / t
• Where:
- Initial velocity (u) = 6 m/s
- Final velocity (v) = 12 m/s
- Time taken (t) = 3 seconds
• Plugging in the values: a = (12 - 6) / 3
• a = 6 / 3 = 2 m/s².
Information Booster:
• SI Unit: The standard international unit for acceleration is meters per second squared (m/s²).
• Vector Quantity: Acceleration is a vector quantity, meaning it has both magnitude and direction. Since the cyclist is speeding up in a straight line, the acceleration is positive and acts in the direction of motion.
• Deceleration: If the cyclist were braking and slowing down from 12 m/s to 6 m/s, the acceleration would be -2 m/s², commonly called deceleration or retardation.
Additional Knowledge:
• Mathematical Trap (Option C): 6 m/s is the total change in velocity (v - u), but failing to divide by time (3s) results in this incorrect answer.
• Mathematical Trap (Option D): 0.5 is obtained by inverting the formula to time / change in velocity (3 / 6), which violates the physical definition of acceleration.
Explanation:
• Acceleration is defined as the rate of change of velocity with respect to time.
• The mathematical formula for uniform acceleration is: a = (v - u) / t
• Where:
- Initial velocity (u) = 6 m/s
- Final velocity (v) = 12 m/s
- Time taken (t) = 3 seconds
• Plugging in the values: a = (12 - 6) / 3
• a = 6 / 3 = 2 m/s².
Information Booster:
• SI Unit: The standard international unit for acceleration is meters per second squared (m/s²).
• Vector Quantity: Acceleration is a vector quantity, meaning it has both magnitude and direction. Since the cyclist is speeding up in a straight line, the acceleration is positive and acts in the direction of motion.
• Deceleration: If the cyclist were braking and slowing down from 12 m/s to 6 m/s, the acceleration would be -2 m/s², commonly called deceleration or retardation.
Additional Knowledge:
• Mathematical Trap (Option C): 6 m/s is the total change in velocity (v - u), but failing to divide by time (3s) results in this incorrect answer.
• Mathematical Trap (Option D): 0.5 is obtained by inverting the formula to time / change in velocity (3 / 6), which violates the physical definition of acceleration.