RRB JE Bodmas Questions with Detailed Solutions

Given
Expression: 110 - 42 × (5 + 6) - 6
Solution
110 - 42 × (5 + 6) - 6 
= 110 - 42 × 11 - 6
= 110 - 462 -6
= -358
Final Answer
So the correct answer is (d)

Given:
Expression: 52 - {38 ÷ (4 × 7 - 9)}
Solution:
52 - {38 ÷ (4 × 7 - 9)}

= 52 - {38 ÷ (28 - 9)}

= 52 - {38 ÷ (19)}

= 52 - 2

= 50

Final Answer
So the correct answer is (a)

Given

Expression = 88 - 1 × (5 + 12) - 19
Solution
88 - 1 × (5 + 12) - 19
= 88 - 17 - 19
= 88 - 36
= 52

Final Answer
So the correct answer is (a)

Given:
Expression: 294 ÷ [10 ÷ 5 × {11 + 12 − (8 + 5 − (10 + 1))}]
Formula Used:
BODMAS Rule (Brackets, Orders, Division, Multiplication, Addition, Subtraction)
Solution:
294 ÷ [10 ÷ 5 × {11 + 12 − (8 + 5 − (10 + 1))}]

= 294 ÷ [2 × {11 + 12 − (8 + 5 − (11))}]

= 294 ÷ [2 × {11 + 12 − (13 − (11))}]

= 294 ÷ [2 × {11 + 12 − (2)}]

= 294 ÷ [2 × {11 + 10}]

= 294 ÷ [2 × {21}]

= 294 ÷ [42]

= 7
Final Answer
So the correct answer is (a)

Given
Mathematical expression:  $$178 - 7 \times (3 + 17) + 22$$​​
Formula Used
BODMAS Rule (Brackets, Orders, Division, Multiplication, Addition, Subtraction)
Solution
Step 1: Solve inside the bracket.
3 + 17 = 20
Substitute into the expression: 178 - 7 \times 20 + 22
Step 2: Perform multiplication.
7 $$\times$$​ 20 = 140
Substitute into the expression: 178 - 140 + 22
Step 3: Perform addition and subtraction from left to right.
178 - 140 = 38
38 + 22 = 60
Final Answer
So the correct answer is (d)

​

Given
Expression: 23 - [3 - {9 - (4 + 5)}]
Solution
​$$23 - [3 - {9 - (4 + 5)}] \\ = 23 - [3 - {9 - 9}] \\= 23 - [3 - 0] \\= 23- 3\\= 20$$​​
Final Answer
So the correct answer is (a)

Given:

33 ÷ 9 × 3 - 2 × 3​

Concept Used:

$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} &[],{}, () \\ \hline \text{Orders, of} & ^x(power), √ (root) , of \\ \hline \text{Division}& ÷ \\\hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\\hline\end{array}$$

Solution:

33 ÷ 9 × 3 - 2 × 3​

=$$\frac{33}{9}$$× 3 - 2 × 3​

=11 - 2 × 3​

=11 -6

=5

Given:

32 ÷ 12 × 3 - 2 × 4 

Concept Used:  

$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline \text{Brackets} &[],{}, () \\ \hline \text{Orders, of} & (power), √ (root) , of \\ \hline \text{Division}& ÷ \\ \hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\\hline \end{array}$$​

Solution: 

= 32 ÷ 12 × 3 - 2 × 4 

= 32 × $$\frac1{12}$$ × 3 -2 × 4

= 8 - 8 

= 0 

Given: 

16 + 16 ÷ 4 - 3 × 4 

Concept Used: ​

BODMAS rule: 

​$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}$$ 

Solution: ​

16 + 16 ÷ 4 - 3 × 4  

= 16 + 4 - 3 × 4 

=  16 + 4 - 12

= 20 - 12 

= 8  

Given: ​

32 ÷ 12 × 3 - 3 × 4 

Concept Used: ​

BODMAS rule: 

​$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}$$ 

Solution: ​

32 ÷ 12 × 3 - 3 × 4  

= 32 ÷ 12 × 3 - 3 × 4 

= $$\frac{32}{12} \times 3 - 3\times 4$$ 

= 8 - 12 

= - 4 

Given: 

16 + 18 ÷ 3 - 3 × 3 

Concept used:

$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}$$​

Solution:

$$16 + 18 \div 3 - 3 \times 3$$ 

$$=16 + 6 - 3 \times 3$$ 

$$=16 + 6 - 9$$ 

$$= 22 - 9$$ 

$$= 13$$ 

​

Given: ​

35.63 - 47.058 + 10.36 - 24.28 + 5.316 $$\times$$​ 5 

Solution: 

​$$35.63 - 47.058 + 10.36 - 24.28 + 5.316 × 5 \\ \ \\ =\frac{3563}{100}-\frac{47058}{1000}+\frac{1036}{100}-\frac{2428}{100}+\frac{5316}{1000}\times5 \\ \ \\ =\frac{2171}{100}-\frac{47058}{1000}+\frac{26580}{1000}\\ \ \\ =\frac{2171}{100}-\frac{20478}{1000} \\ \ \\ =\frac{21710 - 20478}{1000}\\ \ \\ = \frac{ 1232}{1000} \\ \ \\ = \frac{154}{125} = 1\frac{29}{125}$$​​

 Given : 

$$16 + 18 ÷ 6 - 2 × 3$$​ 

Concept Used :

BODMAS Rule: 

$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}$$​

Solution : 

​$$16 + 18 \div 6 - 2 \times 3$$​​

$$=16 + 3 - 6$$ 

$$= 19 - 6$$ 

$$= 13$$​​​

Given: 

16 + 16 ÷ 4 - 3 × 3 

Concept Used: 

​$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}$$​​

Solution: 

16 + 16 ÷ 4 - 3 × 3 

= 16 + 4 - 3 × 3  

= 16 + 4 - 9 

= 20 - 9 

= 11