Write a Pythagorean triplet whose smallest member is 8.

Correct option is B

Given:

We need to find a Pythagorean triplet with the smallest member as 8.

Concept Used:
A Pythagorean triplet consists of three positive integers a, b, c such that:

​$$a^2 + b^2 = c^2$$​​

where c is the hypotenuse (largest number).

Solution:
Check each option:

A: 8, 18, 28
$$8^2 + 18^2 = 64 + 324 = 388 \neq 784 = 28^2$$​ (not correct)

B: 8, 15, 17
$$8^2 + 15^2 = 64 + 225 = 289 = 17^2$$​ ( correct)

C: 8, 15, 19
$$8^2 + 15^2 = 289 \neq 361 = 19^2$$​ (not correct)

D: 8, 10, 12
$$8^2 + 10^2 = 64 + 100 = 164 \neq 144 = 12^2$$​(not correct)