Of the three angles of a triangle, one is twice the smallest and another one is thrice the smallest. Find the value of the smallest angle.

Correct option is C

Given:

The three angles of a triangle.

One angle is twice the smallest angle.

Another angle is thrice the smallest angle.

Concept Used:

The sum of the angles of a triangle is always 1$$80^\circ.$$​​

Solution:

Let the smallest angle be x. Then:

The second angle is 2x (twice the smallest).

The third angle is 3x (thrice the smallest).

x + 2$$x + 3x = 180^\circ$$​

6x$$= 180^\circ$$​

x =$$\frac{180^\circ}{6} = 30^\circ$$​

The smallest angle is $$30^\circ.$$​​