If the sides of a triangle are in the ratio of 1:√3:2, then what is the ratio of its corresponding angles ?

Correct option is D

Given:
Ratio of sides a:b:c = $$1 : \sqrt{3} : 2$$​​
Formula Used:
Pythagoras theorem$$a^2 + b^2 = c^2$$​ and Trigonometric ratios.
Solution:
Let the sides be $$x, \sqrt{3}x$$​, and 2x.
Notice that $$x^2 + (\sqrt{3}x)^2 = x^2 + 3x^2 = 4x^2$$​​
Also, $$(2x)^2 = 4x^2$$​​
Since the sum of the squares of two smaller sides equals the square of the largest side, it is a right-angled triangle.
The angle opposite to the hypotenuse (2x) is $$90^\circ.$$​​
Let the angle opposite to the side x be A.
​$$\sin(A) = \frac{Perpendicular}{Hypotenuse} = \frac{x}{2x} = \frac{1}{2}$$​​
Therefore, $$A = 30^\circ.$$​​
The other acute angle opposite to $$\sqrt{3}x$$ is $$90^\circ - 30^\circ = 60^\circ.$$​​
The corresponding angles are $$30^\circ, 60^\circ,$$​ and $$90^\circ.$$​​
Ratio of the angles = 30 : 60 : 90 = 1 : 2 : 3.
Final Answer
So the correct answer is (d)