Correct option is D
Given:
In △ABC, BD ⟂ AC at D and ∠DBC = 22°. E is a point on BC such that ∠CAE = 36°.
Formula Used:
Sum of angles in a △ = 180°.
Solution:

In △BDC, since BD ⟂ AC:
∠BDC = 90°.
We have, ∠DBC = 22°.
Then, ∠BDC + ∠DCB + ∠DBC = 180°
90° + ∠DCB + 22° = 180°
∠DCB = 180° − 112°
∠DCB = 68°.
In △AEC, ∠CAE = 36°.
Then, ∠AEB = ∠CAE + ∠DCB
∠AEB = 36° + 68°
∠AEB = 104°.
