In an isosceles triangle, the vertex angle measures 76°. What is the measure of each ofthe base angles?
Given:
The vertex angle of the isosceles triangle = 76°
Formula Used:
In an isosceles triangle, the sum of the base angles and the vertex angle is 180°.
If the vertex angle is θ, then the base angles (each of them x) can be found using the formula:
2x + θ = 180°
Solution:
The vertex angle = 76°
Substitute this into the equation:
2x + 76° = 180°
2x = 180° - 76° = 104°
x = 104° / 2 = 52°
Each equal angle = 52°
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