While covering a distance of 37 km, a man noticed that after cycling for 1 hour 5 minutes, the distance covered by him was $$\frac{4}{3}$$ of the remaining distance. What was his speed (in km/hr, rounded off to one decimal place)?​

Correct option is B

Given:

Total distance = 37 km

Time taken = 1 h 5 min = $$\frac{13}{12}$$​ h

Distance covered after this time =$$\frac{4}{3}$$​ of the remaining distance

Formula Used:

Speed $$=\dfrac{\text{distance}}{\text{time}}$$​​

Solution:

If covered distance x, remaining = 37 - x

Condition: x$$=\frac{4}{3}(37-x)$$

3x = 148 - 4x

7x = 148

x =$$\frac{148}{7}\text{ km}$$​​

​$$\text{Speed}=\frac{x}{13/12}=\frac{148}{7}\times\frac{12}{13}=\frac{1776}{91}\approx 19.5\ \text{km/h}$$​​