Which smallest number should be added to 22938 so that the sum is completely divisible by 7?

Correct option is C

Given:

Number = 22938

We need to find the smallest number to be added so that the sum is completely divisible by 7

Solution:

22938 ÷ 7 = 3276  remainder 6

So,
Smallest number to add = 7 - 6 = 1