Correct option is C
Given:
Options: 622, 584, 534, 608
Concept Used:
Divisible by 6
must be divisible by both 2 and 3.
Divisibility by 2
last digit must be even.
Divisibility by 3
sum of digits must be divisible by 3.
Solution:
622
last digit 2 (even) ; sum = 6+2+2 = 10 (not divisible by 3) Not divisible
584
last digit 4 (even) ; sum = 5+8+4 = 17 (not divisible by 3) Not divisible
534
last digit 4 (even) ; sum = 5+3+4 = 12 (divisible by 3) Divisible
608
last digit 8 (even) ; sum = 6+0+8 = 14 (not divisible by 3) Not divisible
Final Answer: 534