Which of the following numbers is divisible by 2, 5, 10 and 11?

Correct option is C

Given:
We need to find the smallest number that is divisible by 2, 5, 10, and 11.
Formula Used:
A number is divisible by 2 if its last digit is even.
A number is divisible by 5 if its last digit is 0 or 5.
A number is divisible by 10 if its last digit is 0.
A number is divisible by 11 if the difference between the sum of digits at odd positions and the sum of digits at even positions is a multiple of 11.
Solution:
A. 203467 - Last digit is 7 (not divisible by 2, 5, or 10).
B. 830942 - Last digit is 2 (divisible by 2, but not by 5 or 10).
C. 589270 - Last digit is 0 (divisible by 2, 5, and 10).
Checking divisibility by 11:
- Sum of digits at odd positions: 5 + 9 + 7 = 21
- Sum of digits at even positions: 8 + 2 + 0 = 10
- Difference = 21 - 10 = 11 (divisible by 11)
D. 1234560 - Last digit is 0 (divisible by 2, 5, and 10).
- Sum of digits at odd positions: 1 + 3 + 5 + 0 = 9
- Sum of digits at even positions: 2 + 4 + 6 = 12
- Difference = 9 - 12 = -3 (not divisible by 11)
The number 589270 is divisible by 2, 5, 10, and 11
Correct answer: Option C (589270).