Which of the following is RHS of the equation
 $$\sqrt{\frac{1+SinA}{1- SinA}}$$ =

Correct option is A

Given:

LHS = $$\sqrt{\frac{1+SinA}{1- SinA}}$$  

Formula Used: 

​$$\frac{1}{\sec A} = \cos A \\ \ \\ \tan A = \frac{\sin A}{\cos A}$$​​

Solution:

LHS= $$\sqrt{\frac{1+SinA}{1- SinA}}$$

Multiply numerator and denominator by 1+ Sin A

=$$\sqrt{\frac{1+SinA}{1-SinA}\times \frac{1+SinA}{1+SinA}}$$ 

$$=\sqrt{\frac{(1+SinA)^2}{1-Sin^2A}}$$

​​​$$=\sqrt{\frac{(1+SinA)^2}{cos^2A}}$$

$$=\frac{1+SinA}{CosA}$$

= secA + tanA = RHS