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Which of the following is not a pythagorian triplet?
Question

Which of the following is not a pythagorian triplet?

A.

5, 12, 13

B.

7, 24, 25

C.

8, 15, 17

D.

9, 40, 49

Correct option is D

Given:
Four sets of numbers as options.

Formula Used:
Pythagorean triplet condition: For a triplet (a,b,c) where c is the largest number, a2+b2=c2a^{2}+b^{2}=c^{2}​.

Solution:
Let us check each option using the Pythagorean theorem.
For Option A (5, 12, 13):
​52+122=25+144=1695^{2}+12^{2}=25+144=169​​
​132=16913^{2}=169​​
This forms a Pythagorean triplet.
For Option B (7, 24, 25):
​72+242=49+576=625252=6257^{2}+24^{2}=49+576=625\\25^{2}=625​​
This forms a Pythagorean triplet.
For Option C (8, 15, 17):
​82+152=64+225=289172=2898^{2}+15^{2}=64+225=289\\17^{2}=289​​
This forms a Pythagorean triplet.
For Option D (9, 40, 49):
​92+402=81+1600=1681492=24019^{2}+40^{2}=81+1600=1681\\49^{2}=2401​​
Here, the sum of the squares of the two smaller numbers is not equal to the square of the largest number.
​1681≠24011681\neq2401​​
Therefore, (9, 40, 49) is not a Pythagorean triplet. The correct triplet would be (9, 40, 41).

Final Answer
So the correct answer is (d)

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