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In △ABC, BD ⟂ AC at D and ∠DBC = 14°. E is a point on BC such that ∠CAE = 75°. What is the measure of ∠AEB?
Question

In △ABC, BD ⟂ AC at D and ∠DBC = 14°. E is a point on BC such that ∠CAE = 75°. What is the measure of ∠AEB?

A.

136°

B.

151°

C.

166°

D.

137°

Correct option is B

Given
BD is perpendicular to AC at D (∠BDC=90∘\angle BDC = 90^{\circ}​)
​∠DBC=14∘∠CAE=75∘\angle DBC = 14^{\circ} \\\angle CAE = 75^{\circ}​​
Formula Used
Sum of angles in a triangle =180∘ 180^{\circ}​​
Angles on a straight line add up to 180∘180^{\circ}​​
Solution
In right-angled triangle BDC, the sum of angles is 180∘.180^{\circ}.​​
​∠C=180∘−90∘−14∘=76∘\angle C = 180^{\circ} - 90^{\circ} - 14^{\circ} = 76^{\circ}​​
In triangle AEC, the sum of angles is 180∘.180^{\circ}.​​
​∠AEC+∠CAE+∠C=180∘ ∠AEC+75∘+76∘=180∘ ∠AEC+151∘=180∘ ∠AEC=29∘ \angle AEC + \angle CAE + \angle C = 180^{\circ} \\\ \\\angle AEC + 75^{\circ} + 76^{\circ} = 180^{\circ}\\\ \\\angle AEC + 151^{\circ} = 180^{\circ}\\\ \\\angle AEC = 29^{\circ}\\\ \\​​
Since points B, E, and C lie on a straight line, angles AEB and AEC are a linear pair.
​∠AEB=180∘−∠AEC\angle AEB = 180^{\circ} - \angle AEC​​
​∠AEB=180∘−29∘=151∘\angle AEB = 180^{\circ} - 29^{\circ} = 151^{\circ}​​
Final Answer
So the correct answer is (b)

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