When $$2^{256}$$​ is divided by 17, the remainder would be:

Correct option is D

Solution:
The term $$2^{256}$$​ can be written as $$(2^4)^{64}$$​​
This can be further expressed as, $$(17-1)^{64}$$​​
In this expansion, all terms will be divisible by 17, except $$(-1)^{64}$$​​
As the term is negative but the power is even, so answer will be positive.
So, the remainder will be 1.