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    What would be the maximum value of Q in the following equation? 5P9 + 3R7+2Q8= 1114
    Question

    What would be the maximum value of Q in the following equation?
    5P9 + 3R7+2Q8= 1114

    A.

    8

    B.

    9

    C.

    7

    D.

    5

    Correct option is B

    Given:

    5P9+3R7+2Q8=11145P9 + 3R7+2Q8= 1114 

    Maximum value of Q = ?

    Solution:

    5P9+3R7+2Q8=11145P9+3R7+2Q8=1114 

    It can be written as: 

    (500 + 10P + 9) + (300 + 10R + 7) + (200 + 10Q + 8) = 1114

    Now,

    500 + 300 + 200 + 10P + 10R + 10Q + 9 + 7 + 8 = 1114

    1000 + 10P + 10R + 10Q + 24 = 1114

    1024 + 10P + 10R + 10Q = 1114

    10P + 10R + 10Q = 90

    P + R + Q = 9

    The smallest possible values for P and R are both 0 (since they are single digits).

    So, if P=0 and R=0, then: 

    Q = 9

    Thus the maximum value of Q is 9.

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