Correct option is DR=V2PWhere:∙R=Resistance (in ohms)∙V=Voltage (in volts)∙P=Power (in watts)Given:∙Power, P=200 W∙Voltage, V=250 VR=2502200=62500200=312.5 ΩR = \frac{V^2}{P}\\[10pt]\textbf{Where:} \\\bullet R = \text{Resistance (in ohms)} \\\bullet V = \text{Voltage (in volts)} \\\bullet P = \text{Power (in watts)}\\[10pt]\textbf{Given:} \\\bullet \text{Power, } P = 200\, \text{W} \\\bullet \text{Voltage, } V = 250\, \text{V}\\[10pt]R = \frac{250^2}{200} = \frac{62500}{200} = 312.5\, \OmegaR=PV2Where:∙R=Resistance (in ohms)∙V=Voltage (in volts)∙P=Power (in watts)Given:∙Power, P=200W∙Voltage, V=250VR=2002502=20062500=312.5Ω