Correct option is C
When capacitors are connected in parallel, the total capacitance is the sum of the individual capacitances. Given that each capacitor has a capacitance of 100 μF, the total capacitance Ctotal can be calculated as follows:
Ctotal = C1 + C2
Here,
C1 = 100 μF
C2 = 100 μF
So,
Ctotal = 100 μF + 100 μF = 200 μF
Thus, the total capacitance of the parallel combination is 200 μF.
The correct answer is 200 μF.