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Two identical capacitors, each having a capacitance of 100 μF are connected in parallel. Find the total capacitance of the parallel combination.
Question

Two identical capacitors, each having a capacitance of 100 μF are connected in parallel. Find the total capacitance of the parallel combination.

A.

400 μF

B.

50 μF

C.

200 μF

D.

100 μF

Correct option is C

When capacitors are connected in parallel, the total capacitance is the sum of the individual capacitances. Given that each capacitor has a capacitance of 100μF, the total capacitance Ctotal can be calculated as follows:Ctotal=C1+C2Here,C1=100μFC2=100μFSo,Ctotal=100μF+100μF=200μFThus, the total capacitance of the parallel combination is 200μF.The correct answer is 200μF.\text{When capacitors are connected in parallel, the total capacitance is the sum of the individual capacitances. Given that each capacitor has a capacitance of 100}\mu F, \text{ the total capacitance } C_{\text{total}} \text{ can be calculated as follows:}\\C_{\text{total}} = C_1 + C_2\\\text{Here,}\\C_1 = 100 \mu F\\C_2 = 100 \mu F\\\text{So,}\\C_{\text{total}} = 100 \mu F + 100 \mu F = 200 \mu F\\\text{Thus, the total capacitance of the parallel combination is } 200 \mu F.\\\text{The correct answer is } 200 \mu F.​​

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