Question

What is the value of ?

A.

2√3

B.

2.5

C.

3.5

D.

3√2

Correct option is B

Given: 
53cos60otan30o3cos0o+3cos245o+2sin60o5\sqrt{3}\cos60^o\tan30^o-3\cos0^o + 3 \cos^245^o+2\sin60^o 
Formula Used:  
Trigonometric value of sin , cos, tan 
θ030456090sin(θ)01222321cos(θ)13222120tan(θ)01313undefinedcosec(θ)undefined22231sec(θ)12322undefinedcot(θ)undefined31130\begin{array}{|c|c|c|c|c|c|}\hline\bf {\theta} & \bf 0^\circ & \bf30^\circ &\bf45^\circ & \bf60^\circ &\bf 90^\circ \\\hline\bf \sin(\theta) & 0 & \frac{1}{2} & \frac{\sqrt{2}}{2} & \frac{\sqrt{3}}{2} & 1 \\\hline\bf \cos(\theta) & 1 & \frac{\sqrt{3}}{2} & \frac{\sqrt{2}}{2} & \frac{1}{2} & 0 \\\hline\bf \tan(\theta) & 0 & \frac{1}{\sqrt{3}} & 1 & \sqrt{3} & \text{undefined} \\\hline\cosec(\theta) & \text{undefined} & 2 & \sqrt{2} & \frac{2}{\sqrt{3}} & 1 \\\hline\sec(\theta) & 1 & \frac{2}{\sqrt{3}} & \sqrt{2} & 2 & \text{undefined} \\\hline\cot(\theta) & \text{undefined} & \sqrt{3} & 1 & \frac{1}{\sqrt{3}} & 0 \\\hline\end{array}​​
Solution: 

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