What is the value of $$\frac{sin 27^o \times cos68^o}{sin22^o \times cos63^o}$$?​

Correct option is A

Given:

​$$\frac{sin 27^o \times cos68^o}{sin22^o \times cos63^o}$$

Formula Used:

​$$\sin(\Theta) = \cos(90^\circ - \Theta)$$ 

sin 27$$\degree= cos(90-27)\degree = cos 63\degree$$

sin 22$$\degree= cos(90-22)\degree = cos 68\degree$$ 

Solution:

​$$\frac{sin 27^o \times cos68^o}{sin22^o \times cos63^o}\\\ \\=\frac{cos63^o \times cos68^o}{cos68^o \times cos63^o}\\=1$$​​