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What is the value of 64x3+36x2 y+24xy2+2y3, when x = 3 and y = -4 ?
Question

What is the value of 64x3+36x2 y+24xy2+2y3, when x = 3 and y = -4 ?

A.

304

B.

1456

C.

1584

D.

432

Correct option is B

Given:
Expression: 64x3+36x2y+24xy2+2y3.64x^3 + 36x^2 y + 24xy^2 + 2y^3.​​
x = 3 and y = −4.
Concept Used: 
Value putting method :
Algebraic expression in two variables is given,
putting the value of two variables and finding the value of the expression.
Solution: 

64 x3+36x2 y+24xy2+2y3
=> x2 (64x + 36y) + 2y2 (12x+y)
=> 32 (64 ×3 + 36(-4) + 2(-4)2 [12 × 3 – 4]
= 9 (192 – 144) + 32 (32)
= 432 + 1024
= 1456 ​​

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