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    What is the value of 64x3+36x2 y+24xy2+2y3, when x = 3 and y = -4 ?
    Question

    What is the value of 64x3+36x2 y+24xy2+2y3, when x = 3 and y = -4 ?

    A.

    304

    B.

    1456

    C.

    1584

    D.

    432

    Correct option is B

    Given:
    Expression: 64x3+36x2y+24xy2+2y3.64x^3 + 36x^2 y + 24xy^2 + 2y^3.​​
    x = 3 and y = −4.
    Concept Used: 
    Value putting method :
    Algebraic expression in two variables is given,
    putting the value of two variables and finding the value of the expression.
    Solution: 

    64 x3+36x2 y+24xy2+2y3
    => x2 (64x + 36y) + 2y2 (12x+y)
    => 32 (64 ×3 + 36(-4) + 2(-4)2 [12 × 3 – 4]
    = 9 (192 – 144) + 32 (32)
    = 432 + 1024
    = 1456 ​​

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