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What is the value of 5128×(240149−8811)+2197169\frac{512}{8} \times \left( \frac{2401}{49} - \frac{88}{11} \right) + \frac{2197}{169}8512​×(492401​−11
Question

What is the value of 5128×(2401498811)+2197169\frac{512}{8} \times \left( \frac{2401}{49} - \frac{88}{11} \right) + \frac{2197}{169}​ ?

A.

2647

B.

2547

C.

2637

D.

2537

Correct option is C

Given:
Expression:5128×(2401498811)+2197169\frac{512}{8} \times \left( \frac{2401}{49} - \frac{88}{11} \right) + \frac{2197}{169}
Concept Used:

Operation preference wiseSymbolBrackets[],,()Orders,of²(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin {array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}
Solution:

5128×(2401498811)+2197169=5128×(498)+13=64×41+13=2637 \frac{512}{8} \times \left( \frac{2401}{49} - \frac{88}{11} \right) + \frac{2197}{169}\\=\frac{512}{8} \times (49 - 8) + 13\\ = 64 \times 41 + 13 = 2637​​

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