Correct option is B
Given:0.97×1.94−1.94×0.03+0.03×0.060.973+0.033Formula used:a3+b3=(a+b)(a2−ab+b2)Solution:Let a=0.97,b=0.03,a+b=1=>Numerator=a3+b3=(a+b)(a2−ab+b2)=a2−ab+b2Denominator:1.94=2asince 2×0.97=1.940.97×1.94=a×2a=2a21.94×0.03=2a×b=2ab0.03×0.06=b×2b=2b2=>Denominator=2a2−2ab+2b2=2(a2−ab+b2)=>2(a2−ab+b2)a2−ab+b2=21∴The value=21