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Value of0.97×0.97×0.97+0.03×0.03×0.030.97×1.94−1.94×0.03+0.03×0.06 \frac{0.97 \times 0.97 \times 0.97 + 0.03 \times 0.03 \times 0.03}{0.97 \times 1.94
Question

Value of0.97×0.97×0.97+0.03×0.03×0.030.97×1.941.94×0.03+0.03×0.06 \frac{0.97 \times 0.97 \times 0.97 + 0.03 \times 0.03 \times 0.03}{0.97 \times 1.94 - 1.94 \times 0.03 + 0.03 \times 0.06}​ is equal to:

A.

1/4

B.

1/2

C.

1/3

D.

1

Correct option is B

Given:0.973+0.0330.97×1.941.94×0.03+0.03×0.06Formula used:a3+b3=(a+b)(a2ab+b2)Solution:Let a=0.97, b=0.03, a+b=1=>Numerator=a3+b3=(a+b)(a2ab+b2)=a2ab+b2Denominator:1.94=2asince 2×0.97=1.940.97×1.94=a×2a=2a21.94×0.03=2a×b=2ab0.03×0.06=b×2b=2b2=>Denominator=2a22ab+2b2=2(a2ab+b2)=>a2ab+b22(a2ab+b2)=12The value=12\textbf{Given:}\\[6pt]\frac{0.97^3 + 0.03^3}{0.97 \times 1.94 - 1.94 \times 0.03 + 0.03 \times 0.06}\\[12pt]\textbf{Formula used:}\\[6pt]a^3 + b^3 = (a + b)(a^2 - ab + b^2)\\[12pt]\textbf{Solution:}\\[6pt]\text{Let } a = 0.97,\; b = 0.03,\; a + b = 1\\[10pt]\Rightarrow \text{Numerator} = a^3 + b^3= (a + b)(a^2 - ab + b^2)\\[6pt]= a^2 - ab + b^2\\[12pt]\text{Denominator:}\\[6pt]1.94 = 2a \quad \text{since } 2 \times 0.97 = 1.94\\[6pt]0.97 \times 1.94 = a \times 2a = 2a^2\\[6pt]1.94 \times 0.03 = 2a \times b = 2ab\\[6pt]0.03 \times 0.06 = b \times 2b = 2b^2\\[10pt]\Rightarrow \text{Denominator}= 2a^2 - 2ab + 2b^2= 2(a^2 - ab + b^2)\\[12pt]\Rightarrow\frac{a^2 - ab + b^2}{2(a^2 - ab + b^2)} = \frac{1}{2}\\[12pt]\therefore \text{The value} = \frac{1}{2}​​

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