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    What should replace '?' in the equation given below? ​51017÷71234−325=(?)25\frac{10}{17}\div 7\frac{12}{34}-\frac{3}{25}=(?)^251710​÷73412​−253​=(?)2
    Question

    What should replace '?' in the equation given below?
    51017÷71234325=(?)25\frac{10}{17}\div 7\frac{12}{34}-\frac{3}{25}=(?)^2​​

    A.

    4/5

    B.

    2/5

    C.

    3/5

    D.

    3/4

    Correct option is A

    Given:
    Equation: 51017÷71234325=(?)25\frac{10}{17}\div 7\frac{12}{34}-\frac{3}{25}=(?)^2​​
    Solution:
    51017÷71234325 =9517÷12517325 =9517×17125325 =95125325 =1925325 =16255\frac{10}{17}\div 7\frac{12}{34}-\frac{3}{25} \\ \ \\= \frac{95}{17}\div \frac{125}{17}-\frac{3}{25}\\ \ \\= \frac{95}{17}\times \frac{17}{125}-\frac{3}{25}\\ \ \\= \frac{95}{125}-\frac{3}{25}\\ \ \\= \frac{19}{25}-\frac{3}{25}\\ \ \\= \frac{16}{25}​​
    Equate to the squared unknown:
    ?2=1625?^2 = \frac{16}{25}​​
    ? = 45 \frac{4}{5}​​
    Final Answer
    So the correct answer is (a)

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