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Find the value of  (168)×{402+116×(8−2)}\left( \frac{16}{8} \right) \times \left\{ \frac{40}{2} + \frac{11}{6} \times (8 - 2) \right\}(816​)
Question

Find the value of  (168)×{402+116×(82)}\left( \frac{16}{8} \right) \times \left\{ \frac{40}{2} + \frac{11}{6} \times (8 - 2) \right\}​​

A.

78

B.

62

C.

76

D.

68

Correct option is B

Given:
(168)×{402+116×(82)}\left( \frac{16}{8} \right) \times \left\{ \frac{40}{2} + \frac{11}{6} \times (8 - 2) \right\} 
Solution:

(168)×{402+116×(82)} =2×{20+116×6} =2×{20+11} =2×31 =62 \left( \frac{16}{8} \right) \times \left\{ \frac{40}{2} + \frac{11}{6} \times (8 - 2) \right\}\\\ \\= 2 \times \left\{ {20 + \frac{11}{6} \times 6}\right\}\\\ \\= 2 \times \left\{ {20+11}\right\}\\\ \\= 2 \times 31\\\ \\= 62\\\ \\​​

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