What is the minimum value of  $$\frac{\sin^2 A + 5 \sin A + 1}{\sin A} \quad \text{for} \quad 0 < A \leq \frac{\pi}{2}$$ ?​

Correct option is C

Given:

$$\frac{\sin^2 A + 5 \sin A + 1}{\sin A} \quad \text{for} \quad 0 < A \leq \frac{\pi}{2}$$​

Concept Used:

The minimum Value of x+1xx+1x  is always 2.

Calculation:

=> Sin A + 5 + 1sinA1sinA

So, the minimum value of Sin A +1sinA1sinA = 2

Minimum Value of the given expression,

=> 2 + 5 = 7

∴ The correct answer is 7.