What is the least number which when increased by 7 is divisible by 16, 18, 24 and 28?

Correct option is C

Given:

Number given are 16,18,24 and 28

Formula Used:

LCM is the number which is divisible by all numbers

Prime factorization

Solution:

Here Prime Factorization of 16,18,24 and 28 is:

16 =$$2^4$$​​

18 =$$2\times 3^2$$​​

24=$$2^3 \times 3$$​​

28=$$2^2 \times 7$$​​

LCM $$= 2^4 \times 3^2 \times 7$$​= 1008

The number to be divided by 16,18,24 and 28 should be increased by 7 hence 1008 should be decreased by 7

= 1008 - 7 = 1001