What is the least number which when divided by 7, 14, 18 and 24 leaves remainder 6 in each case?

Correct option is A

Given:

We need to find the least number that when divided by 7, 14, 18, and 24 leaves a remainder of 6 in each case.

Solution:

LCM of 7, 14, 18, and 24

Factorize each number:
7 = 7
14 = 2 × 7
18 = $$2 \times 3^2$$​​
24 = $$2^3 \times 3$$​​

LCM = 2$$^3 \times 3^2 \times 7 = 8 \times 9 \times 7 = 5$$​04

Least number is:

LCM of (7, 14, 18, 24) + 6 = 504 + 6 = 510