Correct option is D
Given:
The number is 1a5a01 and it must be divisible by 11.
Concept Used:
A number is divisible by 11 if the difference between the sum of its digits at odd positions and the sum of its digits at even positions is either 0 or divisible by 11.
Solution:
Let us take the digits of the number 1a5a01 at odd and even positions.
Odd positions: 1, 5, 0
Even positions: a, a, 1
The sum of digits at odd positions is:
1 + 5 + 0 = 6
The sum of digits at even positions is:
a + a + 1 = 2a + 1
According to the divisibility rule of 11:
6 - (2a + 1) = 5 - 2a
For the number to be divisible by 11, 5 - 2a must be divisible by 11.
Try different values of a to satisfy the condition.
If a = 3, 5 - 2(3) = 5 - 6 = -1, which is not divisible by 11.
If a = 4, 5 - 2(4) = 5 - 8 = -3, which is not divisible by 11.
If a = 8, 5 - 2(8) = 5 - 16 = -11, which is divisible by 11.
Therefore, the digit that comes in place of a is 8.