Given series 0.25, 2.25, 6.25, 12.25, ?
= 2.25 - 0.25 = 2
= 6.25 - 2.25 = 4
= 12.25 - 6.25 = 6
Now, as difference between the fourth and third term is 6. So, the difference between the fifth and fourth term = 6 + 2 = 8
Add 8 in fourth term to get fifth term,
Fifth term = 12.25 + 8
Fifth term = 20.25
Thus, the sequence become,
0.25, 2.25, 6.25, 12.25, 20.25
English
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12 Mins English English50 Questions100 Marks60 Mins English English10 Questions20 Marks12 Mins EnglishFor different sets of datasets X and Y. correlation coefficient between X and Y, that is R and standard deviation of X and Y, that is, S(X) and S(Y) are given in A-D below. Estimate the covariance between X and Y for each dataset and arrange in ascending order.
A. R= 0.5, S(X)= 8, S(Y)= 10
B. R= 4/7, S(X)= 7, S(Y)= 9
C. R= 0.7, S(X)= 12, S(Y)= 5
D. R= 19/42, S(X)= 14, S(Y)= 6
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Suggested Test Series
Suggested Test Series
