What are the order and degree respectively of the differential equation

​$$\left( 2 - \left( \frac{dy}{dx} \right)^2 \right)^{0.6} = \frac{d^2 y}{dx^2}$$​​

Correct option is D

​$$\left( 2 - \left( \frac{dy}{dx} \right)^2 \right)^{0.6} = \frac{d^2 y}{dx^2}\\\left( 2 - \left( \frac{dy}{dx} \right)^2 \right)^{\frac{3}{5}} = \frac{d^2 y}{dx^2}\\\left( 2 - \left( \frac{dy}{dx} \right)^2 \right)^3 = \left( \frac{d^2 y}{dx^2} \right)^5\\\text{The order and degree are 2 and 5 respectively.}$$​​