Correct option is A
Given:
Two trains start from Stations A and Stations B.
They travel towards each other at 60 km/h and 40 km/h.
By the time they meet, the faster train has travelled 60 km more than the slower train.
Concept used:
For opposite direction,
Relative speed, Sr= S1+ S2
Distance = Speed time
Solution:
let time taken by train to meet be t.
Distance covered by the Train A = 60t
Distance covered by the Train B = 40t
Difference in distance = 60t - 40t = 20t
Now, 20t = 60
t = 3
So, Total distance between the two stations
60t + 40t = 100t
= 100 × 3
= 300 km
Distance between the two stations 300km.