Two trains one from station P to Q, the other from station Q to P start simultaneously with speeds 80 km/h and 95km/h. If they meet after 12 hours, what is the difference between the distances covered by them?

Correct option is D

Given:

Speed of the first train: $$80 \, \text{km/h}$$​​

Speed of the second train: $$95 \, \text{km/h}$$​​

Time taken to meet: $$12 \, \text{hours}$$​​

Formula Used:

The distance covered by the first train:  $$d_1 = \text{Speed of first train} \times \text{Time}$$​ 

The distance covered by the second train: $$d_2 = \text{Speed of second train} \times \text{Time}$$​​

The difference between the distances covered by the two trains is:

​$$Delta d = d_2 - d_1$$​​

Solution:
Substitute the values into the formulas:

​$$d_1 = 80 \times 12 = 960 \, \text{km}\\\ \\d_2 = 95 \times 12 = 1140 \, \text{km}$$​​

Therefore, the difference in distances is:

​$$\Delta d = 1140 - 960 = 180 \, \text{km}$$​​

Therefore, the difference between the distances covered by the two trains is 180 km.