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    Two stations, A and B are 100 km apart on a straight line. One train starts from A at 7 A.M. and travels towards B at a speed of 20 km/h. Another trai
    Question

    Two stations, A and B are 100 km apart on a straight line. One train starts from A at 7 A.M. and travels towards B at a speed of 20 km/h. Another train starts from B at 8 A.M. and travels towards A at a speed of 25 km/h. At what time they will meet?

    A.

    10 : 47a.m.

    B.

    11 : 05a.m.

    C.

    10 : 37a.m.

    D.

    9 : 47a.m.

    Correct option is D

    Given:

    Distance between A and B = 100km

    Train starts from A at 7:00AM at 20km/hr

    Another train starts from B at 8:00AM at 25km/hr

    Formula Used:

    Time=DistanceSpeedTime = \frac{Distance}{Speed}​​

    Solution:

    Distance travelled by train one from 7:00AM to 8:00AM:

    Time = 1hour

    =20km/hr×1=20km 20km/hr \times 1 = 20km​​

    Distance left when another train starts from station B = 100 - 20 = 80km

    Relative speed when both train A and B are moving towards each other = 20 + 25 = 45km/hr

    Time taken to meet =8045=169hour=179hour \frac{80}{45} = \frac{16}{9}hour = 1\frac{7}{9}hour​​

    Time in minutes = 1hourand79×60=1 hour and 46.6minutes1 hour and \frac{7}{9} \times 60 = 1\ hour\ and \ 46.6minutes​​

    Time from 8:00AM + 1 hour 47 minutes = 9 : 47min

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