Two resistors of 2Ω each are connected in series to a battery of 4 V . The current in Ampere flowing through the resistors will be:

Correct option is B

​The correct answer is (b) 1

Explanation:

When two resistors are connected in series, the total resistance (R_total) is the sum of the individual resistances.

Given:

• Resistance of each resistor = 2 Ω
• Battery voltage = 4 V
• ​$$R_{\text{total}} = 2 \, \Omega + 2 \, \Omega = 4 \, \Omega$$​​

Now, we can calculate the current using Ohm's Law:

                                 $$I = \frac{V}{R}​$$​

Where:

• I is the current in amperes,
• V is the voltage (4 V),
• R is the total resistance (4 Ω).

Substituting the values:

​$$I = \frac{4 \, \text{V}}{4 \, \Omega} = 1 \, \text{A}$$​​

So, the current flowing through the resistors is 1 Ampere.

Information Booster:

Series Connection: In a series connection, the current is the same through all components, and the total resistance is the sum of the individual resistances.

Ohm's Law: Ohm's Law states that the current (I) flowing through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor.

                                              $$I = \frac{V}{R}$$​​