Two letters are selected from the word 'TENDULKAR'. The probability that both are vowels is:

Correct option is B

Given:
Word: TENDULKAR

Task: Select 2 letters at random.
Find the probability that both selected letters are vowels.
Concept Used:
Probability = $$\frac{\text{Favorable outcomes}}{\text{Total outcomes}}$$​​
Combination formula: C(n, k) = $$\frac{n!}{k!(n - k)!}$$​​
Solution:
Total letters in "TENDULKAR":
T, E, N, D, U, L, K, A, R → Total letters = 9
Total vowels in "TENDULKAR":
E, U, A → Vowels = 3
Total consonants = 9 - 3 = 6 
Total ways to choose 2 letters out of 9:

C(9, 2) = $$\frac{9 \times 8}{2 \times 1} = 36$$​
Favorable outcomes (both letters are vowels):
C(3, 2) =$$\frac{3 \times 2}{2 \times 1} = 3$$​

Probability $$=\frac{\text{Favorable outcomes}}{\text{Total outcomes}} = \frac{3}{36} = \frac{1}{12}$$​